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प्रश्न
The mass of gas adsorbed, x per unit mass of adsorbed, m was measured at various x pressures p. A graph between `log "x"/"m"` and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of `"x"/"m"` at a pressure of 4 atm is ______.
[Given log 3 = 0.4771]
पर्याय
2
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6
8
उत्तर
The mass of gas adsorbed, x per unit mass of adsorbed, m was measured at various x pressures p. A graph between `log "x"/"m"` and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of `"x"/"m"` at a pressure of 4 atm is 6.
Explanation:
From Freundlich's adsorption isotherms equation
We get,
`"x"/"m" = "Kp"^(1//"n")`
⇒ `log("x"/"n") = log "k" + 1/"n" log "p"`
Here slope = `1/"n"` = 2
Intercept = log K = 0.4771
∴ K = Antilog 0.4771 = 3
∴ n = `1/2`
∴ `"x"/"m" = 3 xx (4)^(1//2)` = 6