Question

The maximum kinetic energy of the photoelectrons ejected will be ______ eV when the light of wavelength 350 nm is incident on a cesium surface. The work function of cesium = 1.9 eV.

पर्याय

• 1.60

• 1.50

• 1.40

• 1.20

Answer 1

The maximum kinetic energy of the photoelectrons ejected will be 1.60 eV when the light of wavelength 350 nm is incident on a cesium surface. The work function of cesium = 1.9 eV.

Explanation:

Given: `phi = 1.9` eV,

λ = 350 nm eV

`hυ = (1242  "nm eV")/(350  "nm")`

hυ = 3.5 eV

K_max = hυ - φ

= 3.5 eV - 1.9 eV

= 1.6 eV