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प्रश्न
The mean of the number a, b, 5, 8, 10 is 6 and variance is 6.80. Then, which one of the following gives possible values of a and b?
पर्याय
a = 3 and b = 4
a = 0 and b = 7
a = 5 and b = 2
a = 1 and b = 6
MCQ
उत्तर
a = 3 and b = 4
Explanation:
According to the question,
6.80 = `((6 - a)^2 + (6 - b)^2 + (6 - 5)^2 + (6 - 8)^2 + (6 - 10)^2)/5`
`\implies` 34 = (6 – a)2 + (6 – b)2 + 1 + 4 + 16
`\implies` (6 – a)2 + (6 – b)2 = 13 = 9 + 4
`\implies` (6 – a)2 + (6 – b)2 = 32 + 22
∴ a = 3, b = 4
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Variance
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