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The metal complex ion that is paramagnetic is ______. (Atomic number of Fe = 26, Cu = 29, Co = 27 and Ni = 28) - Chemistry (Theory)

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प्रश्न

The metal complex ion that is paramagnetic is ______.

(Atomic number of Fe = 26, Cu = 29, Co = 27 and Ni = 28)

पर्याय

  • [Fe(CN)4]2−

  • [Co(NH3)6]3+

  • [Ni(CN4)]2−

  • [Cu(NH3)4]2+

MCQ
रिकाम्या जागा भरा

उत्तर

The metal complex ion that is paramagnetic is [Cu(NH3)4]2+.

Explanation:

Paramagnetic substances have unpaired electrons, while diamagnetic substances have all electrons paired

  1. [Fe(CN)4]2−
    Assume x is the oxidation number of Fe in given complex.
    x + 4(−1) = −2
    x − 4 = − 2
    x = − 2 + 4
    = + 2
    Electronic configuration of Fe = [Ar]3d64s2
    Fe+2 = [Ar]3d6
    All electrons are paired; hence, it is diamagnetic in nature [Co(NH3)6]3+
  2. Assume x is the oxidation number of Co in given complex.
    x + 6(0) = + 3
    x = + 3
    Electronic configuration of Co = [Ar] 3d74s2
    Co+3 = [Ar]3d6
  3. All electrons are paired; hence, it is diamagnetic [Ni(CN4)]2−
    Assume x is the oxidation number of Ni in the given complex.
    x + 4(−1) =− 2
    x − 4 = − 2
    x = + 2
    Electronic configuration of Ni = [Ar] 3d84s2
    Ni2+ = [Ar]3d8
  4. All electrons are paired, hence, it is diamagnetic [Cu(NH3)4]2+.
    Assume x is the oxidation number of Cu in the given complex.
    x + 4(0) = + 2
    x = + 2
    Electronic configuration of Cu = [Ar] 3d10 4s1
    Cu−2 = [Ar]3d9
    It has one unpaired electron; hence, it is paramagnetic.
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