Question

The number of isomeric alcohols possible with the formula C₄H₁₀O is ____________.

पर्याय

• 3

• 4

• 5

• 6

Answer 1

The number of isomeric alcohols possible with the formula C₄H₁₀O is 4.

Explanation:

The number of isomeric alcohols possible with the formula C₄H₁₀O is 4 which are as follows:

\[\ce{\underset{{n}-Butyl alcohol}{CH3CH2CH2CH2OH}}\]

\[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
|\\
\ce{CH3 - C - OH}\\
|\\
\phantom{...}\ce{\underset{tert-Butyl alcohol}{CH3}}
\end{array}\]

\[\ce{\underset{sec-Butyl alcohol}{CH3CH2CHOHCH3}}\]

\[\begin{array}{cc}
\ce{CH3}\phantom{...}\\
|\phantom{......}\\
\ce{\underset{lsobutyl alcohol}{CH3 - CH - CH2OH}}
\end{array}\]