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The observation 29, 32, 48, 50, x, x+2, 72, 78, 84, 95 are arranged in ascending order. What is the value of x if the median of the data is 63?
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If number of observations is even, then the median will be the average of `(n/2)th and the (n/2+1)`th observations.
In the given case, ЁЭСЫ=10тЯ╣`(n/2)`ЁЭСбтДО=5 ЁЭСбтДО ЁЭСОЁЭСЫЁЭСС `(n/2+1)`ЁЭСбтДО=6ЁЭСбтДО ЁЭСЬЁЭСПЁЭСаЁЭСТЁЭСЯЁЭСгЁЭСОЁЭСбЁЭСЦЁЭСЬЁЭСЫ.
Thus, 63=`(x+(x+2))/2`
тЯ╣126=2ЁЭСе+2
тЯ╣ 124=2ЁЭСе
тЯ╣ ЁЭСе=62
Thus, the value of x is 62.
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