Advertisements
Advertisements
प्रश्न
The pH of 0.005M codeine (C18H21NO3) solution is 9.95. Calculate its ionization constant and pKb.
उत्तर
c = 0.005
pH = 9.95
pOH = 4.05
pH = – log (4.105)
`4.05 = -log["OH"^-]`
`["OH"^-] = 8.91 xx 10^(-5)`
`"c" alpha = 8.91 xx 10^(-5)`
`alpha = (8.91 xx 10^(-5))/(5xx10^(-3)) = 1.782 xx 10^(-2)`
Thus `"K"_"b" = "c" alpha^2`
`= 0.005 xx (1.782)^2 xx 10^(-4)`
`= 0.005 xx 3.1755 xx 10^(-4)`
`= 0.0158 xx 10^(-4)`
`"K"_"b" = 1.58 xx 10^(-6)`
`"Pk"_"b" = - log "K"_"b"`
`= - log (1.58 xx 10^(-6))`
= 5.80
APPEARS IN
संबंधित प्रश्न
If 0.561 g of KOH is dissolved in water to give 200 mL of solution at 298 K. Calculate the concentrations of potassium, hydrogen and hydroxyl ions. What is its pH?
Choose the most correct answer:
The pH of 10-8 M of HCl is ______.
Choose the most correct answer:
Which of the following solution will have a pH value equal to 1.0?
Which complex among the following gives a white precipitate on treatment with an aqueous solution of barium chloride?
The pH of 0.001 M HCl solution is ______.
Which of the following is CORRECT for an aqueous solution of NH4CN?
[Ka of HCN = 4.0 × 10−10, Kb for NH4OH = 1.8 × 10−5]
The number of ions given by Na3[Fe(CN)6] in aqueous solution is ____________.
pH of a saturated solution of Ca(OH)2 is 9. The Solubility product (Ksp) of Ca(OH)2
What is the pH of the resulting solution when equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed?
A lab assistant prepared a solution by adding a calculated quantity of HCl gas at 25°C to get a solution with [H3O+]= 4 × 10−5 M. Is the solution neutral (or) acidic (or) basic.
Acidity of \[\ce{BF3}\] can be explained on the basis of which of the following concepts?
Define pH.
Define pH.
Define pOH.
Define pH.
Derive a relationship between pH and pOH.
Define pH.
Derive the relation pH + pOH = 14.
