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प्रश्न
The point in the interval [0, 2π], where f(x) = ex sin x has maximum slope, is ______.
पर्याय
`π/4`
`π/2`
π
`(3π)/2`
MCQ
रिकाम्या जागा भरा
उत्तर
The point in the interval [0, 2π], where f(x) = ex sin x has maximum slope, is `underlinebb(π/2)`.
Explanation:
Given, f(x) = ex sin x
f'(x) = ex cos x + sin x ex
f''(x) = – ex sin x + cos x ex + ex cos x + ex sin x
= 2ex cos x
For maximum slope,
f''(x) = 0
`\implies` 2ex cos x = 0
`\implies` cos x = 0
`\implies` x = `π/2, (3π)/2, ∀ x ∈ [0, 2π]`
f'''(x) = 2 [–ex sin x + ex cos x]
`f^(''')(x)|_(x = π/2) < 0` and `f^(''')(x)|_(x = (3π)/2) > 0`
∴ SIope is maximum at x = `π/2`.
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