मराठी

The point in the interval [0, 2π], where f(x) = ex sin x has maximum slope, is ______. -

Advertisements
Advertisements

प्रश्न

The point in the interval [0, 2π], where f(x) = ex sin x has maximum slope, is ______.

पर्याय

  • `π/4`

  • `π/2`

  • π

  • `(3π)/2`

MCQ
रिकाम्या जागा भरा

उत्तर

The point in the interval [0, 2π], where f(x) = ex sin x has maximum slope, is `underlinebb(π/2)`.

Explanation:

Given, f(x) = ex sin x

f'(x) = ex cos x + sin x ex

f''(x) = – ex sin x + cos x ex + ex cos x + ex sin x

= 2ex cos x

For maximum slope,

f''(x) = 0

`\implies` 2ex cos x = 0

`\implies` cos x = 0

`\implies` x = `π/2, (3π)/2, ∀  x ∈ [0, 2π]`

f'''(x) = 2 [–ex sin x + ex cos x]

`f^(''')(x)|_(x = π/2) < 0` and `f^(''')(x)|_(x = (3π)/2) > 0`

∴ SIope is maximum at x = `π/2`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×