Advertisements
Advertisements
प्रश्न
The population of a town increases at the rate of 50 per thousand. Its population after 2 years will be 22050. Find its present population.
उत्तर
Population after two years = P \[\left( 1 + \frac{R}{100} \right)^n \]
\[22, 050 = P \left( 1 + \frac{50}{1000} \right)^2 \]
\[22, 050 = P \left( 1 . 05 \right)^2 \]
\[P = \frac{22, 050}{1 . 1025}\]
\[ = 20, 000\]
Thus, the population two years ago was 20, 000.
APPEARS IN
संबंधित प्रश्न
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 3000, Rate = 18%, Time = 2 years
The production of a mixi company in 1996 was 8000 mixies. Due to increase in demand it increases its production by 15% in the next two years and after two years its demand decreases by 5%. What will be its production after 3 years?
Ashish started the business with an initial investment of Rs 500000. In the first year he incurred a loss of 4%. However during the second year he earned a profit of 5% which in third year rose to 10%. Calculate the net profit for the entire period of 3 years.
To start a business, Shalaka has taken a loan of ₹8000 at a rate of 10 `1/2` p.c.p.a. After two years, how much compound interest will she have to pay?
A shepherd has 200 sheep with him. Find the number of sheep with him after 3 years if the increase in the number of sheep is 8% every year.
In a forest there are 40,000 trees. Find the expected number of trees after 3 years if the objective is to increase the number at the rate 5% per year.
A loan of ₹ 15000 was taken on compound interest. If the rate of compound interest is 12 p.c.p.a. find the amount to settle the loan after 3 years.
The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.
In the year 2001, the number of malaria patients admitted in the hospitals of a state was 4,375. Every year this number decreases by 8%. Find the number of patients in 2003.