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प्रश्न
The potential energy of a particle executing S.H.M is 2.5 J, when its displacement is half of amplitude. The total energy of the particle is ______.
पर्याय
2.5 J
10 J
12 J
20 J
MCQ
रिकाम्या जागा भरा
उत्तर
The potential energy of a particle executing S.H.M is 2.5 J, when its displacement is half of amplitude. The total energy of the particle is 10 J.
Explanation:
P.E. = `1/2 "m"omega^2 "x"^2 = 2.5 ` J
As x = `"A"/2`
`therefore 1/2 "m"omega^2 ("A"/2)` = 2.5
`therefore 1/2 "m"omega^2 "A"^2 = 10` J
Total energy of system = `1/2 "m"omega^2 "A"^2 = 10 ` J
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The Energy of a Particle Performing S.H.M.
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