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प्रश्न
The principal value of `tan^-1(tan (9π)/8)` is ______.
पर्याय
`π/8`
`(3π)/8`
`- π/8`
`- (3π)/8`
MCQ
रिकाम्या जागा भरा
उत्तर
The principal value of `tan^-1(tan (9π)/8)` is `underlinebb(π/8)`.
Explanation:
`tan^-1(tan (9π)/8) = tan^-1(tan(π + π/8))`
= `tan^-1(tan π/8)` ...`[∵ π/8 ∈ ((-π)/2, π/2)]`
= `π/8`
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