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प्रश्न
The principal value of `[tan^-1sqrt(3) - cot^-1(-sqrt(3))]` is ______.
पर्याय
π
`-π/2`
0
`2sqrt(3)`
MCQ
रिकाम्या जागा भरा
उत्तर
The principal value of `[tan^-1sqrt(3) - cot^-1(-sqrt(3))]` is `underlinebb(-π/2)`.
Explanation:
We have,
`tan^-1sqrt(3) - cot^-1(-sqrt(3))`
= `π/3 - (π - π/6)`
= `tan^-1(tan π/3) - π + cot^-1 cot π/6`
= `π/3 - (5π)/6`
= `-π/2`
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