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The product of four consecutive natural numbers, which are multiples of fives, is Rs. 15,000. Find those natural numbers.
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Let 5x, 5(x+1), 5(x+2) and 5(x+3) be four consecutive natural numbers, which are multiple of fives.
It is given that product of these consecutive numbers is 15000.
5ЁЭСе×5(ЁЭСе+1) ×5 (ЁЭСе+2) ×5( ЁЭСе+3) = 15000
625×ЁЭСе( ЁЭСе+1)( ЁЭСе+2)( ЁЭСе+3) =15000
ЁЭСе (ЁЭСе+1)( ЁЭСе+2)( ЁЭСе+3) =15000/625
ЁЭСе (ЁЭСе+1)( ЁЭСе+2)( ЁЭСе+3) =24
When ЁЭСе=1 Then,
ЁЭСе (ЁЭСе+1)( ЁЭСе+2)( ЁЭСе+3)
1 (1+1)( 1+2)( 1+3)
1(2)(3)(4) =24
Hence, the four consecutive natural numbers are
5ЁЭСе=5×1=5
5 (ЁЭСе+1) =5× (1+1) =5×2=10
5 (ЁЭСе+2) =5× (1+2) =5×3=15
5 (ЁЭСе+3) =5× (1+3) =5×4=20
Therefore four consecutive natural numbers are 5, 10, 15 and 20.
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