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The Product of Four Consecutive Natural Numbers, Which Are Multiples of Fives, Is Rs. 15,000. Find Those Natural Numbers. - Algebra

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The product of four consecutive natural numbers, which are multiples of fives, is Rs. 15,000. Find those natural numbers.

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Let 5x, 5(x+1), 5(x+2) and 5(x+3) be four consecutive natural numbers, which are multiple of fives. 
It is given that product of these consecutive numbers is 15000.

5ЁЭСе×5(ЁЭСе+1) ×5 (ЁЭСе+2) ×5( ЁЭСе+3) = 15000

625×ЁЭСе( ЁЭСе+1)( ЁЭСе+2)( ЁЭСе+3) =15000

ЁЭСе (ЁЭСе+1)( ЁЭСе+2)( ЁЭСе+3) =15000/625

ЁЭСе (ЁЭСе+1)( ЁЭСе+2)( ЁЭСе+3) =24

When ЁЭСе=1 Then,

ЁЭСе (ЁЭСе+1)( ЁЭСе+2)( ЁЭСе+3)

1 (1+1)( 1+2)( 1+3)

1(2)(3)(4) =24

Hence, the four consecutive natural numbers are

5ЁЭСе=5×1=5

5 (ЁЭСе+1) =5× (1+1) =5×2=10

5 (ЁЭСе+2) =5× (1+2) =5×3=15

5 (ЁЭСе+3) =5× (1+3) =5×4=20

Therefore four consecutive natural numbers are 5, 10, 15 and 20.

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Linear Equation in Two Variables
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2013-2014 (March)

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