Question

The radius of a circle with centre ‘P’ is 10 cm. If chord AB of the circle subtends a right angle at P, find the area of the minor sector by using the following activity. (π = 3.14)

Activity:

r = 10 cm, θ = 90°, π = 3.14

A(P − AXB) = `θ/360 xx square`

= `square/360 xx 3.14 xx 10^2` 

= `1/4 xx square`

A(P − AXB) = `square` sq. cm

Answer 1

r = 10 cm, θ = 90°, π = 3.14

A(P − AXB) = \[\frac\theta{360}\] × \[\boxed{\pi r^2}\]

= \[\frac{\boxed{90}}{360}\] × 3.14 × 10²

= \[\frac{1}{4}\] × \[\boxed{3.14}\] × \[\boxed{100}\]

A(P − AXB) = \[\boxed{78.5}\] sq. cm