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प्रश्न
The relation between time and displacement for two particles is given by Y1 = 0.06 sin 27`pi` (0.04t + `phi_1`), y2 = 0.03sin 27`pi`(0.04t + `phi_2`). The ratio of the intensity of the waves produced by the vibrations of the two particles will be ______.
पर्याय
2: 1
1: 2
4: 1
1: 4
MCQ
रिकाम्या जागा भरा
उत्तर
The relation between time and displacement for two particles is given by Y1 = 0.06 sin 27`pi` (0.04t + `phi_1`), y2 = 0.03sin 27`pi`(0.04t + `phi_2`). The ratio of the intensity of the waves produced by the vibrations of the two particles will be 4: 1.
Explanation:
`"I"_1/"I"_2= ("a"_1^2)/ ("a"_2^2) = (0.06/0.03)^2 = 4/1`
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Acceleration (a), Velocity (v) and Displacement (x) of S.H.M.
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