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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

The roots of the equation 2x2 – 7x + 5 = 0 are α and β. Without solving for the roots, find αβ+βα - Mathematics

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प्रश्न

The roots of the equation 2x2 – 7x + 5 = 0 are α and β. Without solving for the roots, find `alpha/beta + beta/alpha`

बेरीज

उत्तर

2x2 – 7x + 5 = `x^2 - 7/2x + 5/2` = 0

α + β = `7/2`

αβ = `5/2`

`alpha/beta + beta/alpha = (alpha^2 + beta^2)/(alphabeta)`

= `((alpha + beta)^2 - 2alphabeta)/(alphabeta)`

= `(alpha + beta)^2/(alphabeta) - 2`

= `(7/2)^2/(5/2) - 2`

= `49/4 xx 2/5 - 2`

= `49/10 - 2`

= `(49 - 20)/10`

= `29/10`

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Quadratic Equations
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पाठ 3: Algebra - Exercise 3.14 [पृष्ठ १२२]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 3 Algebra
Exercise 3.14 | Q 2. (ii) | पृष्ठ १२२
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