Advertisements
Advertisements
प्रश्न
The roots of the quadratic equation px2 – qx + r = 0 are real and equal if ______.
पर्याय
p2 = 4qr
q2 = 4pr
– q2 = 4pr
p2 > 4pr
उत्तर
The roots of the quadratic equation px2 – qx + r = 0 are real and equal if q2 = 4pr.
Explanation:
Given, equation is px2 – qx + r = 0
On comparing it with ax2 + bx + c = 0, we get
a = p, b = – q, c = r
For roots to be equal, D = 0
i.e., b2 – 4ac = 0
`\implies` (– q)2 – 4 × p × r = 0
`\implies` q2 – 4pr = 0
`\implies` q2 = 4pr
APPEARS IN
संबंधित प्रश्न
Find the value of p, for which one root of the quadratic equation px2 – 14x + 8 = 0 is 6 times the other.
Find the value of k for which the roots are real and equal in the following equation:
3x2 − 5x + 2k = 0
Find the values of k for which the roots are real and equal in each of the following equation:
(k + 1)x2 - 2(3k + 1)x + 8k + 1 = 0
Solve the following quadratic equation using formula method only
`2x^2 - 2 . sqrt 6x + 3 = 0`
Discuss the nature of the roots of the following quadratic equations : `3x^2 - 2x + (1)/(3)` = 0
If a = 1, b = 4, c = – 5, then find the value of b2 – 4ac
The roots of the quadratic equation 6x2 – x – 2 = 0 are:
If the roots of ax2 + bx + c = 0 are in the ratio m : n, then:
If x2 (a2 + b2) + 2x (ac + bd) + c2 +d2 = 0 has no real roots, then:
Find the roots of the quadratic equation by using the quadratic formula in the following:
–x2 + 7x – 10 = 0