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प्रश्न
The set of all values of k for which (tan–1 x)3 + (cot–1 x)3 = kπ3, x ∈ R, is the internal ______.
पर्याय
`[1/32, 7/8)`
`(1/24, 13/16)`
`[1/48, 13/16]`
`[1/32, 9/8)`
उत्तर
The set of all values of k for which (tan–1 x)3 + (cot–1 x)3 = kπ3, x ∈ R, is the internal `underlinebb([1/32, 7/8)`.
Explanation:
Given expression is (tan–1 x)3 + (cot–1 x)3.
= (tan–1 x + cot–1 x)
((tan–1 x)2 + (cot–1 x)2 – tan–1 x cot–1 x)
= `(π/2)((tan^-1x + cot^-1x)^2 - 3tan^-1x cot^-1x)`
= `π^3/8 - (3π)/2 tan^-1 x(π/2 - tan^-1x)`
= `(3π)/2(tan^-1x - π/4)^2 + π^3/32`
Above expression will have a minimum value when `(tan^-1x - π/4)` becomes 0 at x = `π/4`.
So, the minimum value is `π^3/32`.
`\implies tan^-1 x ∈((-π)/2, π/2)`
Therefore, the maximum value occurs at x = `-π/2`.
So, the maximum value is `(7π^3)/8`.
= `π^3/32 ≤ kπ^3 < 7/8π^3`
= `1/32 ≤ k < 7/8`
Required range = `[1/32, 7/8)`