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प्रश्न
The size of the landholdings of 380 families in a village is given below. Find the median size of landholdings.
|
Size of Land Holdings (in acres) |
Less than 100 |
100 - 200 |
200 - 300 |
300 - 400 |
400 and above |
|
Number of families |
40 |
89 |
148 |
64 |
39 |
उत्तर
|
Size of Land Holdings Class Interval |
No. of Families (f) |
Cumulative Frequency (CF) |
|
0 - 100 |
40 |
40 |
|
100 - 200 |
89 |
129 |
|
200 - 300 |
148 |
277 |
|
300 - 400 |
64 |
341 |
|
400 - 500 |
39 |
380 |
|
Total |
`sumf=380` |
`sumf = N = 380`
So, the Median class = Size of `(N/2)^(th)` item = 190th item
190th item lies in the 129th cumulative frequency and the corresponding class interval is 200 - 300.
So, Median `=L+(N/2-CF)/fxxi`
`=200+(190-129)/148xx100`
= `200+61/148xx100`
= 200 + 41.22
= 241.22
The median size of land holdings = 241.22 acres
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