Question

The Slope of the normal to the curve `y = 2x^2 + 3 sin x` at `x` = 0 is

पर्याय

• 3

• `1/3`

• `- 3`

• `- 1/3`

Answer 1

`- 1/3`

Explanation:

The line is `y = 2x^2 + 3 sin x`

`(dy)/(dx) = 4x + 3 cos x`

Let `x` = 0, `(dy)/(dx)` = 3

∴ Slope = 3

∴ Slope of normal is `- 1/m = - (-1)/m`