Advertisements
Advertisements
प्रश्न
The sum of all the natural numbers from 200 to 600 (both inclusive) which are neither divisible by 8 nor by 12 is:
पर्याय
1, 23, 968
1, 33, 068
1, 33, 268
1, 87, 332
उत्तर
1, 33, 268
Explanation:
Sum of no. from 200 to 600
a = 200, d = 1, n = 600 - 200 + 1 = 401
`"S"_401=401/2[200+600]`....{`"S"_"n"="n"/2("a"+"l")`}
`=401/2(800)=401xx400`
⇒ 160400
Sum of numbers divisible by both 8 or 12
= n (8) + n (12) − n (LCM of 8 and 12)
Sum of numbers divisible by 8
`=51/2[200+600]=51xx400=20400`
Sum of numbers divisible by 12
`=34/2(204+600)=17xx804=13668`
Sum of numbers divisible by 24 .....(LCM of 8 and 12)
`=17/2(216+600)=17xx408=6936`
Sum of numbers divisible by 8 or 12
= 20400 + 13668 − 6936 = 27132
Sum of numbers neither divisible by 8 nor 12
= 160400 − 27132 = 133268
APPEARS IN
संबंधित प्रश्न
If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51 . What is the original fraction?
Choose the most appropriate option:
What is the sum of all the natural numbers from 1 to 100?
Product of two expressions ⁄ L.C.M =
Number of methods to find H.C.F are
For two or more algebric expressions, expression of lowest degree which is divisible by each of them without remainder is known as
By multiplying and dividing polynomials with any number during process of finding H.C.F
Two numbers differ by 10. If their LCM is 120 and HCF is 10, then the sum of the numbers is:
Let x be the least number divisible by 8, 12, 30, 36, and 45 and x is also a perfect square. What is the value of x?
What is the sum of the numbers between 300 and 400 such that when they are divided by 6, 12, and 16, it leaves no remainder?
The sum of two numbers is 50 and their product is 525. The LCM of the two numbers is: