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प्रश्न
The surface tension of water is 72 dyne/cm. Convert it in SI unit.
उत्तर
1 dyne = 10−5 N
1 cm = 10−2 m
\[\therefore 72 \text{ dyne /cm }= \frac{72 \times {10}^{- 5} N}{{10}^{- 2} m} = 72 \times {10}^{- 3} N/m = 0 . 072 N/m\]
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