Advertisements
Advertisements
प्रश्न
The taxi fare after each km, when the fare is Rs 15 for the first km and Rs 8 for each additional km, does not form an AP as the total fare (in Rs) after each km is 15, 8, 8, 8,... Is the statement true? Give reasons.
पर्याय
True
False
उत्तर
This statement is False.
Reasons:
Because the total fare (in ?) after each km is
15,(15 + 8), (15 + 2 × 8), (15 + 3 × 8),... = 15, 23, 31, 39,...
Let t1 = 15, t2 = 23, t3 = 31 and t4 = 39
Now, t2 – t1 = 23 – 15 = 8
t3 – t2 = 31 – 23 = 8
t4 – t3 = 39 – 31 = 8
Since, all the successive terms of the given list have same difference
i.e., common difference = 8
Hence, the total fare after each km form an AP.
APPEARS IN
संबंधित प्रश्न
The 13th term of an A.P. is four times its 3rd term. If its 5th term is 16, then find the sum of its first ten terms.
Write the first five terms of the sequence defined by `a_n = (–1)^(n-1) . 2^n`
Following are APs or not? If they form an A.P. find the common difference d and write three more terms:
1, 3, 9, 27 …
Following are APs or not? If they form an A.P. find the common difference d and write three more terms:
12, 32, 52, 72 …
The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7: 15. Find the numbers.
How many terms are there in the A.P.?
7, 10, 13, ... 43.
If seven times the 7th term of an A.P. is equal to eleven times the 11th term, then what will be its 18th term?
Find the first term and common difference of the Arithmetic Progressions whose nth term is given below
tn = – 3 + 2n
The eighth term of an AP is half its second term and the eleventh term exceeds one third of its fourth term by 1. Find the 15th term.
The first term of an A.P. is 22, the last term is –6 and the sum of all the terms is 64. Find the number of terms of the A.P. Also, find the common difference.