Question

The temperature at which the molecules of nitrogen will have the same r.m.s. velocity as the molecules of oxygen at 327° C is ____________.

पर्याय

• 77° C

• 252° C

• 350° C

• 457° C

Answer 1

The temperature at which the molecules of nitrogen will have the same r.m.s. velocity as the molecules of oxygen at 327° C is 252° C.

Explanation:

`("C"_"rms")_"N" = sqrt ((3  "RT"_"N")/("M"_"N")),("C"_"rms")_"O" = sqrt ((3  "RT"_"O")/("M"_"O"))`

`("C"_"rms")_"N" = ("C"_"rms")_"O"`     ....[Given]

`therefore (3  "RT"_"N")/("M"_"N") = (3  "RT"_"O")/("M"_"O")`

`therefore ("T" + 273)/28 = (327 + 273)/32`

`therefore "T" + 273 = 600/32 xx 28 = 525  "K"`

`therefore "T" = 525 - 273`

` = 252° "C"`