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प्रश्न
The time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration `g/2`, the time period of the pendulum will be ______.
पर्याय
`sqrt(3/2)"T"`
`"T"/sqrt3`
`sqrt(2/3)"T"`
`sqrt3"T"`
MCQ
उत्तर
`bb(sqrt(2/3)"T")`
Explanation:
Using the expression,
T = 2π `sqrt(l/g)`
A pseudo force is exerted downwards when the lift moves with an acceleration of `"g"/2` in the upward direction.
Effective acceleration
`g_"eff" = "g" + "g"/2`
= 3g/2
Therefore, the new time period
T' = `2pisqrt(l/("g"_"eff"))`
= `2pisqrt(l/(3"g"//2))`
= `sqrt(2/3)"T"`.
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