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प्रश्न
The value of k for which the pair of linear equations 4x + 6y – 1 = 0 and 2x + ky – 7 = 0 represents parallel lines is
पर्याय
k = 3
k = 2
k = 4
k = − 3
MCQ
उत्तर
k = 3
Explanation;
Hint:
Slope of 4x + 6y – 1 = 0
6y = – 4x + 1
⇒ y = `(-4)/6x + 1/6`
Slope = `(-4)/6 = (-2)/3`
Slope of 2x + ky – 7 = 0
ky = – 2x + 7
y = `(-2)/"k"x + 7/"k"`
Slope of a line = `(-2)/"k"`
Since the lines are parallel
`(-2)/3 = (-2)/"k"`
– 2k = – 6
k = `6/2`
= 3
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