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प्रश्न
The value of k (k < 0) for which the function f defined as
f(x) = `{((1-cos"kx")/("x"sin"x")"," "x" ≠ 0),(1/2"," "x" = 0):}`
is continuous at x = 0 is:
पर्याय
±1
−1
`±1/22`
`1/2`
MCQ
उत्तर
−1
Explanation:
`lim/("x" -> 0) ((1-cos"kx")/("x"sin"x")) = 1/2`
`lim/("x" -> 0) ((2 sin ((2"kx")/2))/("x" sin"x")) = 1/2`
`lim/("x" -> 0) 2 ("k"/2)^2 ((sin ("kx"/2))/("kx"/2))^2 ("x"/sin"x") = 1/2`
k2 = 1 ⇒ k = ±1 but k < 0 ⇒ k = −1
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