Question

The value of `(1 1/3 ÷ 2 6/7  "of"  5 3/5) ÷ (6 2/5 ÷ 4 1/2 "of"  5 1/3) xx (3/4 xx 2 2/3 ÷ 5/9 "of" 1 1/3) xx (3/4 xx 2 2/3 ÷ 5/9 "of"  1 1/5) = 1 + "k"` where k lies between:

पर्याय

• −0.07 and −0.06

• −0.08 and −0.07

• −0.06 and −0.05

• −0.05 and −0.04

Answer 1

−0.07 and −0.06

Explanation:

`(4/3 ÷ 20/7 "of" 28/5) ÷ (32/5 ÷ 9/2 "of" 16/3) xx (3/4 xx 8/3 ÷ 5/9 "of" 6/5) = 1 + "k"`

⇒ `(4/3 ÷ 16) ÷ (32/5 ÷ 24) xx (3/4 xx 4) = 1 + "k"`

⇒ `1/12 ÷ 4/15 xx 3 = 1 + "k"`

⇒ `1/12 xx 15/4 xx 3 = 1 + "k"`

⇒ `"k" = 15/16 - 1 = (-1)/16 = -0.0625`

∴ −0.07 < −0.0625 < −0.06