Question

The volume of hydrogen gas liberated at STP when 23 g of sodium is reacted with ethanol is ____________.

पर्याय

• 22.4 dm³

• 0.5 dm³

• 11.2 dm³

• 1.12 dm³

Answer 1

The volume of hydrogen gas liberated at STP when 23 g of sodium is reacted with ethanol is 11.2 dm³.

Explanation:

The reaction is

\[\ce{2C2H5 - OH + 2Na -> 2C2H5ONa + H2 ^}\]

Now, 23 g sodium = 1 mol sodium

From reaction, 2 mol sodium liberate 1 mol H₂ = 22.4 dm³ H₂

Hence, 1 mol sodium liberates 0.5 mol H₂ = 11.2 dm³ H₂