Question

The volume of oxygen required for complete combustion of 0.25 mole of methane at S.T.P. is ______.

पर्याय

• 22.4 dm³

• 5.6 dm³

• 11.2 dm³

• 7.46 dm³

Answer 1

The volume of oxygen required for complete combustion of 0.25 mole of methane at S.T.P. is 11.2 dm³.

Explanation:

\[\ce{CH4 + 2O2 -> CO2 + 2H2O}\]

1 mole of methane required = 2 × 22.4 dm³ of O₂

∴ 0.25 mole of methane required = 2 × 22.4 × 0.25 = 11.2 dm³ of O₂