Question

The weight of 350 mL of a diatomic gas at 0°C and 2 atm pressures is 1 g. The weight of one atom in gram is: (N = Avogadro's number)

पर्याय

• `16/"N"`

• `32/"N"`

• 16 N

• 32 N

Answer 1

`16/"N"`

Explanation:

PV = nRT

Let the atomic weight be A

`2 xx 350/1000 = 1/(2"A") xx 0.0821 xx 273`

A = `224/14` = 16

Mass of one atom = `16/"N"_"A" "g"`