Question

The weight of CO is required to form Re₂(CO)₁₀ will be ______ g, from 2.50 g of Re₂O₇ according to given reaction

\[\ce{Re2O7 + CO -> Re2(CO)10 + CO2}\]

Atomic weight of Re = 186.2; C = 12 and O = 16.

पर्याय

• 6.023

• 2.456

• 8.952

• 0.256

Answer 1

2.456

Explanation:

Balanced equation is

\[\ce{Re2O7 + 17CO -> Re2(CO)10 + 7 CO2}\] 
484.4      17 × (28) = 476

So, Coagulation value = `(2.5 xx 476)/(484.4)` = 2.456 g