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प्रश्न
The workdone by a gas molecule in an x' isolated system is given by, W = αβ2 `e^(-x^2/(alpha"KT"))`, where x is the displacement, k is the Boltzmann constant and T is the temperature. α and β are constants. Then the dimensions of β will be ______.
पर्याय
[M0LT0]
[M2LT2]
[MLT-2]
[ML2T-2]
उत्तर
The workdone by a gas molecule in an x' isolated system is given by, W = αβ2 `e^(-x^2/(alpha"KT"))`, where x is the displacement, k is the Boltzmann constant and T is the temperature. α and β are constants. Then the dimensions of β will be [MLT-2].
Explanation:
Given, W = αβ2 `e^(-x^2/(alpha"KT"))`
We know that exponents are dimensionless quantities
So, `x^2/(alpha"KT")` = [M0L0T0]
⇒ `["L"^2]/(alpha["ML"^2"T"^-2"K"^-1]["K"])` = [M0L0T0]
⇒ α = [M-1 T2]
⇒ Dimension of work = [ML2 T-2]
⇒ αβ2 = [ML2 T-2]
⇒ β2 [M-1 T2] = [ML2 T-2]
⇒ β2 `("ML"^2"T"^-2)/("M"^-1"T"^2)`
⇒ β2 [M2 T-4 L2]
β = [MT-2 L]
β = [M L T-2]