Question

Three identical spheres, each of mass M, are placed at the comers of a right angle triangle with mutually perpendicular sides equal to 2 m (see figure). Taking the point of intersection of the two mutually perpendicular sides as the origin, find the position vector of centre of mass.

पर्याय

• `4/3(hati + hatj)`

• `2(hati + hatj)`

• `(hati + hatj)`

• `2/3(hati + hatj)`

Answer 1

`2/3(hati + hatj)`

Explanation:

X_cm = `(M xx 0 + M xx 0 + M xx 2)/(3M) = 2/3`

Y_cm = `(M xx 0 + M xx 0 + M xx 2)/(3M) = 2/3`

`vecr_(cm) = 2/3(hati + hatj)`