Advertisements
Advertisements
प्रश्न
Three positive numbers are in the ratio `1/2 : 1/3 : 1/4`. Find the numbers if the sum of their squares is 244.
उत्तर
Given, three positive numbers are in the ratio `1/2 : 1/3 : 1/4 = 6 : 4 : 3`
Let the numbers be 6x, 4x and 3x.
From the given information,
(6x)2 + (4x)2 + (3x)2 = 244
36x2 + 16x2 + 9x2 = 244
61x2 = 244
x2 = 4
x = ± 2
Since, the numbers are positive, so x = 2.
Thus, the numbers are 12, 8 and 6.
APPEARS IN
संबंधित प्रश्न
The sum of the squares of two positive integers is 208. If the square of the large number is 18 times the smaller. Find the numbers.
Find the two natural numbers which differ by 5 and the sum of whose squares is 97.
The sum of a number and its reciprocal is 4.25. Find the number.
Two natural numbers differ by 3. Find the numbers, if the sum of their reciprocals is `7/10`.
The sum of the squares of two consecutive positive even numbers is 52. Find the numbers.
Find two consecutive positive odd numbers, the sum of whose squares is 74.
The denominator of a positive fraction is one more than twice the numerator. If the sum of the fraction and its reciprocal is 2.9; find the fraction.
The sum S of first n even natural numbers is given by the relation S = n(n + 1). Find n, if the sum is 420.
The sum of the squares of two consecutive integers is 41. The integers are ______.
The product of two whole numbers, each greater than 4, is 35; the numbers are ______.
