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प्रश्न
To obtain a magnification of, –0.5 with a convex lens, the object should be placed:
(a) at F
(b) between optical centre and F
(c) between F and 2F
(d) beyond 2F
उत्तर
Beyond 2F: since the magnification is negative and less than 1, the image formed is real, inverted and diminished. Therefore, the object should be placed beyond 2F.
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संबंधित प्रश्न
The height of the image formed by an object of height 10 cm placed in front of a plane mirror is __________.
(a) 5 cm
(b) 10 cm
(c) 15 cm
(d) 20 cm
Where should an object be placed in front of the concave mirror so as to obtain its virtual, erect and magnified image?
The image formed by a concave mirror is virtual, erect and magnified. The position of object is:
(a) at focus
(b) between focus and centre of curvature
(c) at pole
(d) between pole and focus
A virtual, erect and magnified image of an object is to be produced with a concave mirror of focal length 12 cm. Which of the following object distance should be chosen for this purpose?
(i) 10 cm
(ii) 15 cm
(iii) 20 cm
Give reason for your choi
If the magnification of a body of size 1 m is 2, what is the size of the image?
What is the nature of image formed by a concave mirror if the magnification produced by the mirror
+4
What is the ratio of the height of an image to the height of an object known as?
Fill in the following blank with suitable word:
If the magnification has a plus sign, than image is ......... and.........
An object is placed at a distance of 100 cm from a converging lens of focal length 40 cm.
(i) What is the nature of image?
(ii) What is the position of image?
For a plane mirror, magnification m = ______.
