Advertisements
Advertisements
प्रश्न
Two APs have the same common difference. The first term of one AP is 2 and that of the other is 7. The difference between their 10th terms is the same as the difference between their 21st terms, which is the same as the difference between any two corresponding terms. Why?
उत्तर
Suppose there are two AP’s with first terms a and A
And their common differences are d and D respectively
Suppose n be any term
an = a + (n – 1)d
An = A + (n – 1)D
As common difference is equal for both AP’s
We have D = d
Using this we have
An – an = a + (n – 1)d – [A + (n – 1)D]
= a + (n – 1)d – A – (n – 1)d
= a – A
As a – A is a constant value
Therefore, difference between any corresponding terms will be equal to a – A.
APPEARS IN
संबंधित प्रश्न
Find the middle term of the A.P. 6, 13, 20, ... , 216.
In the following situation, involved make an arithmetic progression? and why?
The taxi fare after each km when the fare is ₹ 15 for the first km and ₹ 8 for each additional km.
The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7: 15. Find the numbers.
Find the common difference and write the next four terms of each of the following arithmetic progressions:
1, −2, −5, −8, ...
Find n if the given value of x is the nth term of the given A.P.
`5 1/2, 11, 16 1/2, 22, ......; x = 550`
Find the common difference of the A.P. and write the next two terms \[0, \frac{1}{4}, \frac{1}{2}, \frac{3}{4}, . . . \]
If the sequence t1, t2, t3 … is in A.P. then the sequence t6, t12, t18 … is
1, 6, 11, 16 ...... Find the 18th term of this A.P.
Determine k so that k2 + 4k + 8, 2k2 + 3k + 6, 3k2 + 4k + 4 are three consecutive terms of an AP.
Which term in the A.P. 60, 56, 52, 48, 44, 40, ...... is the first negative term?