Advertisements
Advertisements
प्रश्न
Two long straight thin wires AB and CD have linear charge densities 10 μC/m and −20 μC/m, respectively. They are kept parallel to each other at a distance 1 m. Find magnitude and direction of the net electric field at a point midway between them.
संख्यात्मक
उत्तर
Given, λ1 = 10 µC/m
λ2 = −20 μC/m
d = 1 m
For a point at a distance from linear charge,
`E = lambda/(2 pi epsilon_0 r)`
Total electric field,
E = E1 + E2
`E = lambda_1/(2 pi epsilon_0 r) + lambda_2/(2 pi epsilon_0 r)`
`E = 2/(4 pi epsilon_0 r)(lambda_1 + lambda_2)`
`E = (2 xx 10^9 xx 9)/0.5 (10 xx 10^-6 - 20 xx 10^-6)`
E = −36 × 109 × 10−5
E = −3.6 × 105 N/C
The direction of the electric field is towards wire CD.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?