Question

Two moles of an ideal gas are allowed to expand from a volume of 10 dm³ to 2 m³ at 300 K against a pressure of 101.325 KPa. Calculate the work done.

पर्याय

• −201.6 kJ

• 13.22 kJ

• −810.6 J

• −18.96 kJ

Answer 1

−201.6 kJ

Explanation:

V₁ = 10 dm³ = 10⁻² m³

V₂ = 2 m³

P = 101.325 × 10³ pa

Work done is as:

W = −PdV

W = −P(V₂ − V₁)

W = −101.325 × 10³ (1.99)

= −201.6 kJ