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प्रश्न
Two spherical soap bubbles of radii r1 and r2 in vacuum coalesce under isothermal conditions. The resulting bubble has a radius R such that ____________.
पर्याय
R = (r1 + r2)/2
R = [r1r2/(r1 + r2)]
`"R" = sqrt("r"_1^2 + "r"_2^2)`
R = r1 + r2
MCQ
रिकाम्या जागा भरा
उत्तर
Two spherical soap bubbles of radii r1 and r2 in vacuum coalesce under isothermal conditions. The resulting bubble has a radius R such that `underlinebb("R" = sqrt("r"_1^2 + "r"_2^2))`.
Explanation:
Because the bubbles coalesce in a vacuum, there is no temperature change. As a result, the surface energy remains unchanged. This means that the total surface area is unaffected.
Hence `4pi"r"_1^2 + 4pi"r"_2^2 = 4pi"rR"^2`
`"or R" = ["r"_1^2 + "r"_2^2]^(1/2)`
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Surface Tension and Surface Energy
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