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प्रश्न
Using the encoding matrix `[(1,1),(0,1)]` encode and decode the messag I*LOVE*MUMBAI.
बेरीज
उत्तर
A | B | C | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S | T | U | V | W | X | * | Y | Z |
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 27 | 25 | 26 |
I | * | L | O | V | E | * | M | U | M | B | A | I | * |
9 | 27 | 12 | 15 | 22 | 5 | 27 | 13 | 21 | 13 | 2 | 1 | 9 | 27 |
Encoding the message includes the following process.
`[(1,1),(0,1)][(9,12,22,27,12,2,9),(27,15,5,13,13,1,27)]`
`=[(9+27,12+15,22+5,27+13,12+13,2+1,9+27),(27,15,5,13,13,1,27)]`
`=[(36,27,27,40,25,3,36),(27,15,5,13,13,1,27)]`
Hence the encoded message we get as,
36, 27, 27, 15, 27, 5, 40, 13, 25, 13, 3, 1, 36, 27.
Now the process of decoding is as follows.
Inverse of `[(1,1),(0,1)]` is `[(1,-1),(0,1)]`
`[(1,-1),(0,1)]``=[(36,27,27,40,25,3,36),(27,15,5,13,13,1,27)]`
`=[(36-27,27-15,27-5,40-13,25-13,3-1,36-27),(27,15,5,13,13,1,27)]`
`=[(9,12,22,27,12,2,9),(27,15,5,13,13,1,27)]`]
Hence the original message is obtained again after encoding and decoding.
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Application of Inverse of a Matrix to Coding Theory
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