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Using the figures given below, frame problems based on profit percent or loss percent. ​Cost price ₹ 2000, selling price ₹ 1900 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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प्रश्न

Using the figures given below, frame problems based on profit percent or loss percent.

​Cost price ₹ 2000, selling price ₹ 1900

बेरीज

उत्तर

Problem: Avinash bought a mobile phone for Rs 2000 and sold the same for Rs 1900. Find his loss percent.

Cost price of mobile phone = Rs 2000

Selling price of mobile phone = Rs 1900

Since selling price is less than cost price, so there is a loss.

Loss = Cost Price − Selling price

= 2000 − 1900

= Rs 100

Let x % be the loss suffered by Avinash. Then,

`"x"/100 = "loss"/"cost price" = 100/2000`

`=> "x"/100 xx 100 = 100/2000 xx 100`

⇒ x = 5

∴ Avinash suffered a loss of 5% in this transaction.

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पाठ 13: Profit – Loss - Practice Set 34 [पृष्ठ ७२]

APPEARS IN

बालभारती Mathematics [English] 6 Standard Maharashtra State Board
पाठ 13 Profit – Loss
Practice Set 34 | Q 2 | पृष्ठ ७२
बालभारती Integrated 6 Standard Part 3 [English Medium] Maharashtra State Board
पाठ 3.4 Profit-Loss
Practice Set 34 | Q 2. | पृष्ठ ६७

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