Question

Van’t Hoff factor for \[\ce{KCl}\] solution assuming the complete dissociation is ______.

पर्याय

• 1

• 2

• 0.5

• 1.5

Answer 1

Van’t Hoff factor for \[\ce{KCl}\] solution assuming the complete dissociation is 2.

Explanation:

`"Van't Hoff Factor" = "final moles"/"initial moles"`

\[\ce{KCl -> K+ + Cl-}\]

Initial moles = 1; final moles = 2

Van't Hoff Factor = `2/1` = 2