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प्रश्न
उत्तर
Magnification = height of image / height of object.
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संबंधित प्रश्न
A 50 cm tall object is at a very large distance from a diverging lens. A virtual, erect and diminished image of the object is formed at a distance of 20 cm in front of the lens. How much is the focal length of the lens?
The letters on the front of an ambulance are written laterally inverted like 
. Give reason.
State the two convenient rays that are chosen to construct the image by a spherical mirror for a given object? Explain your answer with the help of suitable ray diagrams.
For what position of object, the image formed by a concave mirror is magnified and erect?
An object of height 2 cm is placed at a distance of 20 cm in front of a concave mirror of a focal length of 12 cm. Find the position, size, and nature of the image.
Define the following term in relation to concave mirror.
Focal length
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