Question

What is the cell constant of `"N"/10 "KCl"` solution at 25°C, if conductivity and resistance of a solution is 0.0112 Ω⁻¹ cm⁻¹ and 55.0 Ω respectively?

पर्याय

• 0.616 cm⁻¹

• 0.2 cm⁻¹

• 0.491 cm⁻¹

• 2.0 cm⁻¹

Answer 1

0.616 cm⁻¹

Explanation:

k = 0.0112 Ω⁻¹ cm⁻¹, R = 55.0 Ω

Cell constant, b = k × R

= 0.0112 Ω⁻¹ cm⁻¹ × 55.0 Ω

∴ b = 0.616 cm⁻¹