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प्रश्न
What is the de Broglie wavelength of an electron, which is accelerated from the rest, through a potential difference of 100V?
उत्तर
Potential difference = 100 V = 100 × 1.6 × 10−19 J
λ = `"h"/sqrt(2"mev")`
= `(6.626 xx 10^-34 "Kgm"^2 "s"^-1)/sqrt(2 xx 9.1 xx 10^-31 "Kg" xx 100 xx 1.6 xx 10^-19 "J")`
λ = 1.22 × 10−10 m
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