Question

What is the oxidation state of Cr in \[\ce{K2Cr2O7}\]?

पर्याय

• +4

• +3

• +6

• +5

Answer 1

+6

Explanation:

Let the oxidation state of Cr in \[\ce{K2Cr2O7}\] is x.

∴ 2(+ 1) + 2x + 7(- 2) = 0

∴ 2 + 2x - 14 = 0

∴ 2x - 12 = 0

⇒ 2x = 12

x = + 6