Question

What is the standard emf of the following cell?

\[\ce{Ni_{(s)} | Ni^{2+}_{( aq)} || Au^{3+}_{( aq)} | Au_{(s)}}\]

if \[\ce{E^0_{Ni}}\] = −0.25 V, \[\ce{E^0_{Au}}\] = 1.50 V.

पर्याय

• 1.75 V

• −1.75 V

• 1.25 V

• −1.25 V

Answer 1

1.75 V

Explanation:

\[\ce{E^0_{cell} = E^0_{cathode} - E^0_{anode} = E^0_{Au} - E^0_{Ni}}\]

= 1.50 − (−0.25)

= 1.75 V