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प्रश्न
What is the nature of roots of the quadratic equation 4x2 − 12x − 9 = 0?
उत्तर
The given quadric equation is 4x2 − 12x − 9 = 0
Here, a = 4, b = -12 and, c = -9
As we know that `D = b^2 - 4ac`
Putting the value of
`a = 4, b = -12 and c = -9`
`(-12)^2 - 4 xx 4 xx -9`
= 144 + 144
= 288
Since, D ≥ 0
Therefore, root of the given equation are real and distinct .
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