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प्रश्न
What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?
उत्तर
Given,
Initial pressure, p1 = 1 bar
Initial volume, V1 = 500 dm3
Final volume, V2 = 200 dm3
Since the temperature remains constant, the final pressure (p2) can be calculated using Boyle’s law.
According to Boyle’s law,
`"p"_1"V"_1 = "p"_2"V"_2`
`=>"p"_2 = ("p"_1"V"_1)/"V"_2`
`= (1xx500)/200 "bar"`
`= 2.5" bar"`
Therefore, the minimum pressure required is 2.5 bar.
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संबंधित प्रश्न
What would be the SI unit for the quantity pV2T 2/n?
For real gases the relation between p, V and T is given by van der Waals equation:
`p + (an^2)/V^2 (V - nb) = nRT`
where ‘a’ and ‘b’ are van der Waals constants, ‘nb’ is approximately equal to the total volume of the molecules of a gas. ‘a’ is the measure of magnitude of intermolecular attraction.
Arrange the following gases in the increasing order of ‘b’. Give reason.
\[\ce{O2, CO2, H2, He}\]
For real gases the relation between p, V and T is given by van der Waals equation:
`p + (an^2)/V^2 (V - nb) = nRT`
where ‘a’ and ‘b’ are van der Waals constants, ‘nb’ is approximately equal to the total volume of the molecules of a gas. ‘a’ is the measure of magnitude of intermolecular attraction.
Arrange the following gases in the decreasing order of magnitude of ‘a’. Give reason.
\[\ce{CH4, O2, H2}\]
